4(3i+1)=7(i+2)

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Solution for 4(3i+1)=7(i+2) equation:


Simplifying
4(3i + 1) = 7(i + 2)

Reorder the terms:
4(1 + 3i) = 7(i + 2)
(1 * 4 + 3i * 4) = 7(i + 2)
(4 + 12i) = 7(i + 2)

Reorder the terms:
4 + 12i = 7(2 + i)
4 + 12i = (2 * 7 + i * 7)
4 + 12i = (14 + 7i)

Solving
4 + 12i = 14 + 7i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-7i' to each side of the equation.
4 + 12i + -7i = 14 + 7i + -7i

Combine like terms: 12i + -7i = 5i
4 + 5i = 14 + 7i + -7i

Combine like terms: 7i + -7i = 0
4 + 5i = 14 + 0
4 + 5i = 14

Add '-4' to each side of the equation.
4 + -4 + 5i = 14 + -4

Combine like terms: 4 + -4 = 0
0 + 5i = 14 + -4
5i = 14 + -4

Combine like terms: 14 + -4 = 10
5i = 10

Divide each side by '5'.
i = 2

Simplifying
i = 2

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