4(3h+6)2h=302

Solution for 4(3h+6)2h=302 equation:

4(3h+6)2h=302

We move all terms to the left:

4(3h+6)2h-(302)=0

We multiply parentheses

24h^2+48h-302=0

a = 24; b = 48; c = -302;
Δ = b2-4ac
Δ = 482-4·24·(-302)
Δ = 31296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{31296}=\sqrt{64*489}=\sqrt{64}*\sqrt{489}=8\sqrt{489}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-8\sqrt{489}}{2*24}=\frac{-48-8\sqrt{489}}{48}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+8\sqrt{489}}{2*24}=\frac{-48+8\sqrt{489}}{48}
$