4(3f-2)+1=4(f+1)+5

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Solution for 4(3f-2)+1=4(f+1)+5 equation: 



4(3f-2)+1=4(f+1)+5

We move all terms to the left:

4(3f-2)+1-(4(f+1)+5)=0

We multiply parentheses

12f-(4(f+1)+5)-8+1=0



We calculate terms in parentheses: -(4(f+1)+5), so:

4(f+1)+5

We multiply parentheses

4f+4+5

We add all the numbers together, and all the variables

4f+9

Back to the equation:

-(4f+9)



We add all the numbers together, and all the variables

12f-(4f+9)-7=0

We get rid of parentheses

12f-4f-9-7=0

We add all the numbers together, and all the variables

8f-16=0

We move all terms containing f to the left, all other terms to the right

8f=16

f=16/8

f=2

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