4(3f+1)=2(16-f)

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Solution for 4(3f+1)=2(16-f) equation:



4(3f+1)=2(16-f)
We move all terms to the left:
4(3f+1)-(2(16-f))=0
We add all the numbers together, and all the variables
4(3f+1)-(2(-1f+16))=0
We multiply parentheses
12f-(2(-1f+16))+4=0
We calculate terms in parentheses: -(2(-1f+16)), so:
2(-1f+16)
We multiply parentheses
-2f+32
Back to the equation:
-(-2f+32)
We get rid of parentheses
12f+2f-32+4=0
We add all the numbers together, and all the variables
14f-28=0
We move all terms containing f to the left, all other terms to the right
14f=28
f=28/14
f=2

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