4(3c+4)=8(c-2)

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Solution for 4(3c+4)=8(c-2) equation:


Simplifying
4(3c + 4) = 8(c + -2)

Reorder the terms:
4(4 + 3c) = 8(c + -2)
(4 * 4 + 3c * 4) = 8(c + -2)
(16 + 12c) = 8(c + -2)

Reorder the terms:
16 + 12c = 8(-2 + c)
16 + 12c = (-2 * 8 + c * 8)
16 + 12c = (-16 + 8c)

Solving
16 + 12c = -16 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
16 + 12c + -8c = -16 + 8c + -8c

Combine like terms: 12c + -8c = 4c
16 + 4c = -16 + 8c + -8c

Combine like terms: 8c + -8c = 0
16 + 4c = -16 + 0
16 + 4c = -16

Add '-16' to each side of the equation.
16 + -16 + 4c = -16 + -16

Combine like terms: 16 + -16 = 0
0 + 4c = -16 + -16
4c = -16 + -16

Combine like terms: -16 + -16 = -32
4c = -32

Divide each side by '4'.
c = -8

Simplifying
c = -8

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