4(3c+2)=8(2c-5)

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Solution for 4(3c+2)=8(2c-5) equation:


Simplifying
4(3c + 2) = 8(2c + -5)

Reorder the terms:
4(2 + 3c) = 8(2c + -5)
(2 * 4 + 3c * 4) = 8(2c + -5)
(8 + 12c) = 8(2c + -5)

Reorder the terms:
8 + 12c = 8(-5 + 2c)
8 + 12c = (-5 * 8 + 2c * 8)
8 + 12c = (-40 + 16c)

Solving
8 + 12c = -40 + 16c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-16c' to each side of the equation.
8 + 12c + -16c = -40 + 16c + -16c

Combine like terms: 12c + -16c = -4c
8 + -4c = -40 + 16c + -16c

Combine like terms: 16c + -16c = 0
8 + -4c = -40 + 0
8 + -4c = -40

Add '-8' to each side of the equation.
8 + -8 + -4c = -40 + -8

Combine like terms: 8 + -8 = 0
0 + -4c = -40 + -8
-4c = -40 + -8

Combine like terms: -40 + -8 = -48
-4c = -48

Divide each side by '-4'.
c = 12

Simplifying
c = 12

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