4(3b-5)-2b=10(b-3)-8

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Solution for 4(3b-5)-2b=10(b-3)-8 equation: 


Simplifying
4(3b + -5) + -2b = 10(b + -3) + -8

Reorder the terms:
4(-5 + 3b) + -2b = 10(b + -3) + -8
(-5 * 4 + 3b * 4) + -2b = 10(b + -3) + -8
(-20 + 12b) + -2b = 10(b + -3) + -8

Combine like terms: 12b + -2b = 10b
-20 + 10b = 10(b + -3) + -8

Reorder the terms:
-20 + 10b = 10(-3 + b) + -8
-20 + 10b = (-3 * 10 + b * 10) + -8
-20 + 10b = (-30 + 10b) + -8

Reorder the terms:
-20 + 10b = -30 + -8 + 10b

Combine like terms: -30 + -8 = -38
-20 + 10b = -38 + 10b

Add '-10b' to each side of the equation.
-20 + 10b + -10b = -38 + 10b + -10b

Combine like terms: 10b + -10b = 0
-20 + 0 = -38 + 10b + -10b
-20 = -38 + 10b + -10b

Combine like terms: 10b + -10b = 0
-20 = -38 + 0
-20 = -38

Solving
-20 = -38

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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