4(3b-2)-2(4b-3)=b+13

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Solution for 4(3b-2)-2(4b-3)=b+13 equation: 



4(3b-2)-2(4b-3)=b+13

We move all terms to the left:

4(3b-2)-2(4b-3)-(b+13)=0

We multiply parentheses

12b-8b-(b+13)-8+6=0

We get rid of parentheses

12b-8b-b-13-8+6=0

We add all the numbers together, and all the variables

3b-15=0

We move all terms containing b to the left, all other terms to the right

3b=15

b=15/3

b=5

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