4(3b-11)=64

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Solution for 4(3b-11)=64 equation: 



4(3b-11)=64

We move all terms to the left:

4(3b-11)-(64)=0

We multiply parentheses

12b-44-64=0

We add all the numbers together, and all the variables

12b-108=0

We move all terms containing b to the left, all other terms to the right

12b=108

b=108/12

b=9

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