4(3b-1)=-6+2(6b+1)

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Solution for 4(3b-1)=-6+2(6b+1) equation: 



4(3b-1)=-6+2(6b+1)

We move all terms to the left:

4(3b-1)-(-6+2(6b+1))=0

We multiply parentheses

12b-(-6+2(6b+1))-4=0



We calculate terms in parentheses: -(-6+2(6b+1)), so:

-6+2(6b+1)

determiningTheFunctionDomain
2(6b+1)-6

We multiply parentheses

12b+2-6

We add all the numbers together, and all the variables

12b-4

Back to the equation:

-(12b-4)



We get rid of parentheses

12b-12b+4-4=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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