4(3b-1)+6=4(2b+4)

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Solution for 4(3b-1)+6=4(2b+4) equation: 



4(3b-1)+6=4(2b+4)

We move all terms to the left:

4(3b-1)+6-(4(2b+4))=0

We multiply parentheses

12b-(4(2b+4))-4+6=0



We calculate terms in parentheses: -(4(2b+4)), so:

4(2b+4)

We multiply parentheses

8b+16

Back to the equation:

-(8b+16)



We add all the numbers together, and all the variables

12b-(8b+16)+2=0

We get rid of parentheses

12b-8b-16+2=0

We add all the numbers together, and all the variables

4b-14=0

We move all terms containing b to the left, all other terms to the right

4b=14

b=14/4

b=3+1/2

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