4(3b+1)=26

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Solution for 4(3b+1)=26 equation: 



4(3b+1)=26

We move all terms to the left:

4(3b+1)-(26)=0

We multiply parentheses

12b+4-26=0

We add all the numbers together, and all the variables

12b-22=0

We move all terms containing b to the left, all other terms to the right

12b=22

b=22/12

b=1+5/6

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