4(3a-6)=100-2(a-1)

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Solution for 4(3a-6)=100-2(a-1) equation: 



4(3a-6)=100-2(a-1)

We move all terms to the left:

4(3a-6)-(100-2(a-1))=0

We multiply parentheses

12a-(100-2(a-1))-24=0



We calculate terms in parentheses: -(100-2(a-1)), so:

100-2(a-1)

determiningTheFunctionDomain
-2(a-1)+100

We multiply parentheses

-2a+2+100

We add all the numbers together, and all the variables

-2a+102

Back to the equation:

-(-2a+102)



We get rid of parentheses

12a+2a-102-24=0

We add all the numbers together, and all the variables

14a-126=0

We move all terms containing a to the left, all other terms to the right

14a=126

a=126/14

a=9

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