4(3a-1)=5(4a-1)-(3a-2)

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Solution for 4(3a-1)=5(4a-1)-(3a-2) equation: 



4(3a-1)=5(4a-1)-(3a-2)

We move all terms to the left:

4(3a-1)-(5(4a-1)-(3a-2))=0

We multiply parentheses

12a-(5(4a-1)-(3a-2))-4=0



We calculate terms in parentheses: -(5(4a-1)-(3a-2)), so:

5(4a-1)-(3a-2)

We multiply parentheses

20a-(3a-2)-5

We get rid of parentheses

20a-3a+2-5

We add all the numbers together, and all the variables

17a-3

Back to the equation:

-(17a-3)



We get rid of parentheses

12a-17a+3-4=0

We add all the numbers together, and all the variables

-5a-1=0

We move all terms containing a to the left, all other terms to the right

-5a=1

a=1/-5

a=-1/5

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