4(3a+2)-5(6a-1)=2(a-8)-6(7a-4)+4a

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Solution for 4(3a+2)-5(6a-1)=2(a-8)-6(7a-4)+4a equation: 



4(3a+2)-5(6a-1)=2(a-8)-6(7a-4)+4a

We move all terms to the left:

4(3a+2)-5(6a-1)-(2(a-8)-6(7a-4)+4a)=0

We multiply parentheses

12a-30a-(2(a-8)-6(7a-4)+4a)+8+5=0



We calculate terms in parentheses: -(2(a-8)-6(7a-4)+4a), so:

2(a-8)-6(7a-4)+4a

We add all the numbers together, and all the variables

4a+2(a-8)-6(7a-4)

We multiply parentheses

4a+2a-42a-16+24

We add all the numbers together, and all the variables

-36a+8

Back to the equation:

-(-36a+8)



We add all the numbers together, and all the variables

-18a-(-36a+8)+13=0

We get rid of parentheses

-18a+36a-8+13=0

We add all the numbers together, and all the variables

18a+5=0

We move all terms containing a to the left, all other terms to the right

18a=-5

a=-5/18

a=-5/18

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