4(32-12)=9(z+3)

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Solution for 4(32-12)=9(z+3) equation: 



4(32-12)=9(z+3)

We move all terms to the left:

4(32-12)-(9(z+3))=0

We add all the numbers together, and all the variables

-(9(z+3))+420=0



We calculate terms in parentheses: -(9(z+3)), so:

9(z+3)

We multiply parentheses

9z+27

Back to the equation:

-(9z+27)



We get rid of parentheses

-9z-27+420=0

We add all the numbers together, and all the variables

-9z+393=0

We move all terms containing z to the left, all other terms to the right

-9z=-393

z=-393/-9

z=43+2/3

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