4(3/4n)=3(2/3n-11)

Solution for 4(3/4n)=3(2/3n-11) equation:

4(3/4n)=3(2/3n-11)

We move all terms to the left:

4(3/4n)-(3(2/3n-11))=0


Domain of the equation: 4n)!=0

n!=0/1

n!=0

n∈R



Domain of the equation: 3n-11))!=0

n∈R


We add all the numbers together, and all the variables

4(+3/4n)-(3(2/3n-11))=0

We multiply parentheses

12n-(3(2/3n-11))=0

We multiply all the terms by the denominator


12n*3n-11))-(3(2=0

We add all the numbers together, and all the variables

12n*3n=0

Wy multiply elements

36n^2=0

a = 36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·36·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{72}=0$