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4(3/4k-5)=6(4)
We move all terms to the left:
4(3/4k-5)-(6(4))=0
Domain of the equation: 4k-5)!=0determiningTheFunctionDomain 4(3/4k-5)-64=0
k∈R
We multiply parentheses
12k-20-64=0
We add all the numbers together, and all the variables
12k-84=0
We move all terms containing k to the left, all other terms to the right
12k=84
k=84/12
k=7
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