4(3-z)-24=20z-6(2+4z)

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Solution for 4(3-z)-24=20z-6(2+4z) equation:


Simplifying
4(3 + -1z) + -24 = 20z + -6(2 + 4z)
(3 * 4 + -1z * 4) + -24 = 20z + -6(2 + 4z)
(12 + -4z) + -24 = 20z + -6(2 + 4z)

Reorder the terms:
12 + -24 + -4z = 20z + -6(2 + 4z)

Combine like terms: 12 + -24 = -12
-12 + -4z = 20z + -6(2 + 4z)
-12 + -4z = 20z + (2 * -6 + 4z * -6)
-12 + -4z = 20z + (-12 + -24z)

Reorder the terms:
-12 + -4z = -12 + 20z + -24z

Combine like terms: 20z + -24z = -4z
-12 + -4z = -12 + -4z

Add '12' to each side of the equation.
-12 + 12 + -4z = -12 + 12 + -4z

Combine like terms: -12 + 12 = 0
0 + -4z = -12 + 12 + -4z
-4z = -12 + 12 + -4z

Combine like terms: -12 + 12 = 0
-4z = 0 + -4z
-4z = -4z

Add '4z' to each side of the equation.
-4z + 4z = -4z + 4z

Combine like terms: -4z + 4z = 0
0 = -4z + 4z

Combine like terms: -4z + 4z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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