4(3-x)-2(x-5)=4x+7(2x-5)

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Solution for 4(3-x)-2(x-5)=4x+7(2x-5) equation: 



4(3-x)-2(x-5)=4x+7(2x-5)

We move all terms to the left:

4(3-x)-2(x-5)-(4x+7(2x-5))=0

We add all the numbers together, and all the variables

4(-1x+3)-2(x-5)-(4x+7(2x-5))=0

We multiply parentheses

-4x-2x-(4x+7(2x-5))+12+10=0



We calculate terms in parentheses: -(4x+7(2x-5)), so:

4x+7(2x-5)

We multiply parentheses

4x+14x-35

We add all the numbers together, and all the variables

18x-35

Back to the equation:

-(18x-35)



We add all the numbers together, and all the variables

-6x-(18x-35)+22=0

We get rid of parentheses

-6x-18x+35+22=0

We add all the numbers together, and all the variables

-24x+57=0

We move all terms containing x to the left, all other terms to the right

-24x=-57

x=-57/-24

x=2+3/8

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