4(3-n)+3=n-5(4+n)

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Solution for 4(3-n)+3=n-5(4+n) equation: 


Simplifying
4(3 + -1n) + 3 = n + -5(4 + n)
(3 * 4 + -1n * 4) + 3 = n + -5(4 + n)
(12 + -4n) + 3 = n + -5(4 + n)

Reorder the terms:
12 + 3 + -4n = n + -5(4 + n)

Combine like terms: 12 + 3 = 15
15 + -4n = n + -5(4 + n)
15 + -4n = n + (4 * -5 + n * -5)
15 + -4n = n + (-20 + -5n)

Reorder the terms:
15 + -4n = -20 + n + -5n

Combine like terms: n + -5n = -4n
15 + -4n = -20 + -4n

Add '4n' to each side of the equation.
15 + -4n + 4n = -20 + -4n + 4n

Combine like terms: -4n + 4n = 0
15 + 0 = -20 + -4n + 4n
15 = -20 + -4n + 4n

Combine like terms: -4n + 4n = 0
15 = -20 + 0
15 = -20

Solving
15 = -20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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