4(3-i)+3(-5+2i)=0

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Solution for 4(3-i)+3(-5+2i)=0 equation:


Simplifying
4(3 + -1i) + 3(-5 + 2i) = 0
(3 * 4 + -1i * 4) + 3(-5 + 2i) = 0
(12 + -4i) + 3(-5 + 2i) = 0
12 + -4i + (-5 * 3 + 2i * 3) = 0
12 + -4i + (-15 + 6i) = 0

Reorder the terms:
12 + -15 + -4i + 6i = 0

Combine like terms: 12 + -15 = -3
-3 + -4i + 6i = 0

Combine like terms: -4i + 6i = 2i
-3 + 2i = 0

Solving
-3 + 2i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 2i = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 2i = 0 + 3
2i = 0 + 3

Combine like terms: 0 + 3 = 3
2i = 3

Divide each side by '2'.
i = 1.5

Simplifying
i = 1.5

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