4(3-b)+b=22+2b

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Solution for 4(3-b)+b=22+2b equation:



4(3-b)+b=22+2b
We move all terms to the left:
4(3-b)+b-(22+2b)=0
We add all the numbers together, and all the variables
4(-1b+3)+b-(2b+22)=0
We add all the numbers together, and all the variables
b+4(-1b+3)-(2b+22)=0
We multiply parentheses
b-4b-(2b+22)+12=0
We get rid of parentheses
b-4b-2b-22+12=0
We add all the numbers together, and all the variables
-5b-10=0
We move all terms containing b to the left, all other terms to the right
-5b=10
b=10/-5
b=-2

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