4(3-6)+u=22+2u

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Solution for 4(3-6)+u=22+2u equation: 



4(3-6)+u=22+2u

We move all terms to the left:

4(3-6)+u-(22+2u)=0

We add all the numbers together, and all the variables

u-(2u+22)+4(-3)=0

We add all the numbers together, and all the variables

u-(2u+22)-12=0

We get rid of parentheses

u-2u-22-12=0

We add all the numbers together, and all the variables

-1u-34=0

We move all terms containing u to the left, all other terms to the right

-u=34

u=34/-1

u=-34

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