4(3-5y)=7(5-4y)=0

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Solution for 4(3-5y)=7(5-4y)=0 equation:



4(3-5y)=7(5-4y)=0
We move all terms to the left:
4(3-5y)-(7(5-4y))=0
We add all the numbers together, and all the variables
4(-5y+3)-(7(-4y+5))=0
We multiply parentheses
-20y-(7(-4y+5))+12=0
We calculate terms in parentheses: -(7(-4y+5)), so:
7(-4y+5)
We multiply parentheses
-28y+35
Back to the equation:
-(-28y+35)
We get rid of parentheses
-20y+28y-35+12=0
We add all the numbers together, and all the variables
8y-23=0
We move all terms containing y to the left, all other terms to the right
8y=23
y=23/8
y=2+7/8

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