4(3-2z)=14-2(z-2)

Solution for 4(3-2z)=14-2(z-2) equation:

4(3-2z)=14-2(z-2)

We move all terms to the left:

4(3-2z)-(14-2(z-2))=0

We add all the numbers together, and all the variables

4(-2z+3)-(14-2(z-2))=0

We multiply parentheses

-8z-(14-2(z-2))+12=0


We calculate terms in parentheses: -(14-2(z-2)), so:

14-2(z-2)

determiningTheFunctionDomain
-2(z-2)+14

We multiply parentheses

-2z+4+14

We add all the numbers together, and all the variables

-2z+18

Back to the equation:

-(-2z+18)


We get rid of parentheses

-8z+2z-18+12=0

We add all the numbers together, and all the variables

-6z-6=0

We move all terms containing z to the left, all other terms to the right

-6z=6

z=6/-6

z=-1