4(3-2u)=28

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Solution for 4(3-2u)=28 equation: 



4(3-2u)=28

We move all terms to the left:

4(3-2u)-(28)=0

We add all the numbers together, and all the variables

4(-2u+3)-28=0

We multiply parentheses

-8u+12-28=0

We add all the numbers together, and all the variables

-8u-16=0

We move all terms containing u to the left, all other terms to the right

-8u=16

u=16/-8

u=-2

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