4(3-2a)-2(2-3a)=2(a+3)-(a+8)

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Solution for 4(3-2a)-2(2-3a)=2(a+3)-(a+8) equation: 



4(3-2a)-2(2-3a)=2(a+3)-(a+8)

We move all terms to the left:

4(3-2a)-2(2-3a)-(2(a+3)-(a+8))=0

We add all the numbers together, and all the variables

4(-2a+3)-2(-3a+2)-(2(a+3)-(a+8))=0

We multiply parentheses

-8a+6a-(2(a+3)-(a+8))+12-4=0



We calculate terms in parentheses: -(2(a+3)-(a+8)), so:

2(a+3)-(a+8)

We multiply parentheses

2a-(a+8)+6

We get rid of parentheses

2a-a-8+6

We add all the numbers together, and all the variables

a-2

Back to the equation:

-(a-2)



We add all the numbers together, and all the variables

-2a-(a-2)+8=0

We get rid of parentheses

-2a-a+2+8=0

We add all the numbers together, and all the variables

-3a+10=0

We move all terms containing a to the left, all other terms to the right

-3a=-10

a=-10/-3

a=3+1/3

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