4(3+y)-7=6+3(y+2)

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Solution for 4(3+y)-7=6+3(y+2) equation: 



4(3+y)-7=6+3(y+2)

We move all terms to the left:

4(3+y)-7-(6+3(y+2))=0

We add all the numbers together, and all the variables

4(y+3)-(6+3(y+2))-7=0

We multiply parentheses

4y-(6+3(y+2))+12-7=0



We calculate terms in parentheses: -(6+3(y+2)), so:

6+3(y+2)

determiningTheFunctionDomain
3(y+2)+6

We multiply parentheses

3y+6+6

We add all the numbers together, and all the variables

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

4y-(3y+12)+5=0

We get rid of parentheses

4y-3y-12+5=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7

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