4(3+x)-3(3x-5)=6-x-2(3-x)

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Solution for 4(3+x)-3(3x-5)=6-x-2(3-x) equation: 



4(3+x)-3(3x-5)=6-x-2(3-x)

We move all terms to the left:

4(3+x)-3(3x-5)-(6-x-2(3-x))=0

We add all the numbers together, and all the variables

4(x+3)-3(3x-5)-(6-x-2(-1x+3))=0

We multiply parentheses

4x-9x-(6-x-2(-1x+3))+12+15=0



We calculate terms in parentheses: -(6-x-2(-1x+3)), so:

6-x-2(-1x+3)

determiningTheFunctionDomain
-x-2(-1x+3)+6

We add all the numbers together, and all the variables

-1x-2(-1x+3)+6

We multiply parentheses

-1x+2x-6+6

We add all the numbers together, and all the variables

x

Back to the equation:

-(x)



We add all the numbers together, and all the variables

-6x+27=0

We move all terms containing x to the left, all other terms to the right

-6x=-27

x=-27/-6

x=4+1/2

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