4(3+v)-v=6+6(v+2)

Solution for 4(3+v)-v=6+6(v+2) equation:

4(3+v)-v=6+6(v+2)

We move all terms to the left:

4(3+v)-v-(6+6(v+2))=0

We add all the numbers together, and all the variables

4(v+3)-v-(6+6(v+2))=0

We add all the numbers together, and all the variables

-1v+4(v+3)-(6+6(v+2))=0

We multiply parentheses

-1v+4v-(6+6(v+2))+12=0


We calculate terms in parentheses: -(6+6(v+2)), so:

6+6(v+2)

determiningTheFunctionDomain
6(v+2)+6

We multiply parentheses

6v+12+6

We add all the numbers together, and all the variables

6v+18

Back to the equation:

-(6v+18)


We add all the numbers together, and all the variables

3v-(6v+18)+12=0

We get rid of parentheses

3v-6v-18+12=0

We add all the numbers together, and all the variables

-3v-6=0

We move all terms containing v to the left, all other terms to the right

-3v=6

v=6/-3

v=-2