4(3+u)-y=6+3(y+2)

Solution for 4(3+u)-y=6+3(y+2) equation:

Simplifying
4(3 + u) + -1y = 6 + 3(y + 2)
(3 * 4 + u * 4) + -1y = 6 + 3(y + 2)
(12 + 4u) + -1y = 6 + 3(y + 2)

Reorder the terms:
12 + 4u + -1y = 6 + 3(2 + y)
12 + 4u + -1y = 6 + (2 * 3 + y * 3)
12 + 4u + -1y = 6 + (6 + 3y)

Combine like terms: 6 + 6 = 12
12 + 4u + -1y = 12 + 3y

Add '-12' to each side of the equation.
12 + 4u + -12 + -1y = 12 + -12 + 3y

Reorder the terms:
12 + -12 + 4u + -1y = 12 + -12 + 3y

Combine like terms: 12 + -12 = 0
0 + 4u + -1y = 12 + -12 + 3y
4u + -1y = 12 + -12 + 3y

Combine like terms: 12 + -12 = 0
4u + -1y = 0 + 3y
4u + -1y = 3y

Solving
4u + -1y = 3y

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add 'y' to each side of the equation.
4u + -1y + y = 3y + y

Combine like terms: -1y + y = 0
4u + 0 = 3y + y
4u = 3y + y

Combine like terms: 3y + y = 4y
4u = 4y

Divide each side by '4'.
u = y

Simplifying
u = y