4(3+c)=3(2+c)

Solution for 4(3+c)=3(2+c) equation:

4(3+c)=3(2+c)

We move all terms to the left:

4(3+c)-(3(2+c))=0

We add all the numbers together, and all the variables

4(c+3)-(3(c+2))=0

We multiply parentheses

4c-(3(c+2))+12=0


We calculate terms in parentheses: -(3(c+2)), so:

3(c+2)

We multiply parentheses

3c+6

Back to the equation:

-(3c+6)


We get rid of parentheses

4c-3c-6+12=0

We add all the numbers together, and all the variables

c+6=0

We move all terms containing c to the left, all other terms to the right

c=-6