4(3+c)+c=c+c+4

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Solution for 4(3+c)+c=c+c+4 equation: 



4(3+c)+c=c+c+4

We move all terms to the left:

4(3+c)+c-(c+c+4)=0

We add all the numbers together, and all the variables

4(c+3)+c-(2c+4)=0

We add all the numbers together, and all the variables

c+4(c+3)-(2c+4)=0

We multiply parentheses

c+4c-(2c+4)+12=0

We get rid of parentheses

c+4c-2c-4+12=0

We add all the numbers together, and all the variables

3c+8=0

We move all terms containing c to the left, all other terms to the right

3c=-8

c=-8/3

c=-2+2/3

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