4(3+5y)-4=3+2(2y-2)

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Solution for 4(3+5y)-4=3+2(2y-2) equation: 



4(3+5y)-4=3+2(2y-2)

We move all terms to the left:

4(3+5y)-4-(3+2(2y-2))=0

We add all the numbers together, and all the variables

4(5y+3)-(3+2(2y-2))-4=0

We multiply parentheses

20y-(3+2(2y-2))+12-4=0



We calculate terms in parentheses: -(3+2(2y-2)), so:

3+2(2y-2)

determiningTheFunctionDomain
2(2y-2)+3

We multiply parentheses

4y-4+3

We add all the numbers together, and all the variables

4y-1

Back to the equation:

-(4y-1)



We add all the numbers together, and all the variables

20y-(4y-1)+8=0

We get rid of parentheses

20y-4y+1+8=0

We add all the numbers together, and all the variables

16y+9=0

We move all terms containing y to the left, all other terms to the right

16y=-9

y=-9/16

y=-9/16

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