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4(3+2x)=2(x+3)
We move all terms to the left:
4(3+2x)-(2(x+3))=0
We add all the numbers together, and all the variables
4(2x+3)-(2(x+3))=0
We multiply parentheses
8x-(2(x+3))+12=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
8x-2x-6+12=0
We add all the numbers together, and all the variables
6x+6=0
We move all terms containing x to the left, all other terms to the right
6x=-6
x=-6/6
x=-1
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