4(2z-4)=7(z-2)

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Solution for 4(2z-4)=7(z-2) equation: 



4(2z-4)=7(z-2)

We move all terms to the left:

4(2z-4)-(7(z-2))=0

We multiply parentheses

8z-(7(z-2))-16=0



We calculate terms in parentheses: -(7(z-2)), so:

7(z-2)

We multiply parentheses

7z-14

Back to the equation:

-(7z-14)



We get rid of parentheses

8z-7z+14-16=0

We add all the numbers together, and all the variables

z-2=0

We move all terms containing z to the left, all other terms to the right

z=2

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