4(2z-3)=5(z+12)

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Solution for 4(2z-3)=5(z+12) equation:


Simplifying
4(2z + -3) = 5(z + 12)

Reorder the terms:
4(-3 + 2z) = 5(z + 12)
(-3 * 4 + 2z * 4) = 5(z + 12)
(-12 + 8z) = 5(z + 12)

Reorder the terms:
-12 + 8z = 5(12 + z)
-12 + 8z = (12 * 5 + z * 5)
-12 + 8z = (60 + 5z)

Solving
-12 + 8z = 60 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-12 + 8z + -5z = 60 + 5z + -5z

Combine like terms: 8z + -5z = 3z
-12 + 3z = 60 + 5z + -5z

Combine like terms: 5z + -5z = 0
-12 + 3z = 60 + 0
-12 + 3z = 60

Add '12' to each side of the equation.
-12 + 12 + 3z = 60 + 12

Combine like terms: -12 + 12 = 0
0 + 3z = 60 + 12
3z = 60 + 12

Combine like terms: 60 + 12 = 72
3z = 72

Divide each side by '3'.
z = 24

Simplifying
z = 24

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