4(2z-1)=3(z+2)

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Solution for 4(2z-1)=3(z+2) equation: 



4(2z-1)=3(z+2)

We move all terms to the left:

4(2z-1)-(3(z+2))=0

We multiply parentheses

8z-(3(z+2))-4=0



We calculate terms in parentheses: -(3(z+2)), so:

3(z+2)

We multiply parentheses

3z+6

Back to the equation:

-(3z+6)



We get rid of parentheses

8z-3z-6-4=0

We add all the numbers together, and all the variables

5z-10=0

We move all terms containing z to the left, all other terms to the right

5z=10

z=10/5

z=2

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