4(2z+4)=8-2(z-4)

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Solution for 4(2z+4)=8-2(z-4) equation:


Simplifying
4(2z + 4) = 8 + -2(z + -4)

Reorder the terms:
4(4 + 2z) = 8 + -2(z + -4)
(4 * 4 + 2z * 4) = 8 + -2(z + -4)
(16 + 8z) = 8 + -2(z + -4)

Reorder the terms:
16 + 8z = 8 + -2(-4 + z)
16 + 8z = 8 + (-4 * -2 + z * -2)
16 + 8z = 8 + (8 + -2z)

Combine like terms: 8 + 8 = 16
16 + 8z = 16 + -2z

Add '-16' to each side of the equation.
16 + -16 + 8z = 16 + -16 + -2z

Combine like terms: 16 + -16 = 0
0 + 8z = 16 + -16 + -2z
8z = 16 + -16 + -2z

Combine like terms: 16 + -16 = 0
8z = 0 + -2z
8z = -2z

Solving
8z = -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
8z + 2z = -2z + 2z

Combine like terms: 8z + 2z = 10z
10z = -2z + 2z

Combine like terms: -2z + 2z = 0
10z = 0

Divide each side by '10'.
z = 0.0

Simplifying
z = 0.0

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