4(2z+3)=3(z-1)+5

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Solution for 4(2z+3)=3(z-1)+5 equation: 



4(2z+3)=3(z-1)+5

We move all terms to the left:

4(2z+3)-(3(z-1)+5)=0

We multiply parentheses

8z-(3(z-1)+5)+12=0



We calculate terms in parentheses: -(3(z-1)+5), so:

3(z-1)+5

We multiply parentheses

3z-3+5

We add all the numbers together, and all the variables

3z+2

Back to the equation:

-(3z+2)



We get rid of parentheses

8z-3z-2+12=0

We add all the numbers together, and all the variables

5z+10=0

We move all terms containing z to the left, all other terms to the right

5z=-10

z=-10/5

z=-2

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