4(2z+3)=20

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Solution for 4(2z+3)=20 equation: 



4(2z+3)=20

We move all terms to the left:

4(2z+3)-(20)=0

We multiply parentheses

8z+12-20=0

We add all the numbers together, and all the variables

8z-8=0

We move all terms containing z to the left, all other terms to the right

8z=8

z=8/8

z=1

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