4(2z+3)=15-z

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Solution for 4(2z+3)=15-z equation: 



4(2z+3)=15-z

We move all terms to the left:

4(2z+3)-(15-z)=0

We add all the numbers together, and all the variables

4(2z+3)-(-1z+15)=0

We multiply parentheses

8z-(-1z+15)+12=0

We get rid of parentheses

8z+1z-15+12=0

We add all the numbers together, and all the variables

9z-3=0

We move all terms containing z to the left, all other terms to the right

9z=3

z=3/9

z=1/3

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