4(2y-6)=32

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Solution for 4(2y-6)=32 equation: 



4(2y-6)=32

We move all terms to the left:

4(2y-6)-(32)=0

We multiply parentheses

8y-24-32=0

We add all the numbers together, and all the variables

8y-56=0

We move all terms containing y to the left, all other terms to the right

8y=56

y=56/8

y=7

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