4(2y-6)=-4(y-6)+12

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Solution for 4(2y-6)=-4(y-6)+12 equation:



4(2y-6)=-4(y-6)+12
We move all terms to the left:
4(2y-6)-(-4(y-6)+12)=0
We multiply parentheses
8y-(-4(y-6)+12)-24=0
We calculate terms in parentheses: -(-4(y-6)+12), so:
-4(y-6)+12
We multiply parentheses
-4y+24+12
We add all the numbers together, and all the variables
-4y+36
Back to the equation:
-(-4y+36)
We get rid of parentheses
8y+4y-36-24=0
We add all the numbers together, and all the variables
12y-60=0
We move all terms containing y to the left, all other terms to the right
12y=60
y=60/12
y=5

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