4(2y-3)=3(y+6)y=

Solution for 4(2y-3)=3(y+6)y= equation:

4(2y-3)=3(y+6)y=

We move all terms to the left:

4(2y-3)-(3(y+6)y)=0

We multiply parentheses

8y-(3(y+6)y)-12=0


We calculate terms in parentheses: -(3(y+6)y), so:

3(y+6)y

We multiply parentheses

3y^2+18y

Back to the equation:

-(3y^2+18y)


We get rid of parentheses

-3y^2+8y-18y-12=0

We add all the numbers together, and all the variables

-3y^2-10y-12=0

a = -3; b = -10; c = -12;
Δ = b2-4ac
Δ = -102-4·(-3)·(-12)
Δ = -44
Delta is less than zero, so there is no solution for the equation