4(2y-2)=8(1-y)

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Solution for 4(2y-2)=8(1-y) equation: 



4(2y-2)=8(1-y)

We move all terms to the left:

4(2y-2)-(8(1-y))=0

We add all the numbers together, and all the variables

4(2y-2)-(8(-1y+1))=0

We multiply parentheses

8y-(8(-1y+1))-8=0



We calculate terms in parentheses: -(8(-1y+1)), so:

8(-1y+1)

We multiply parentheses

-8y+8

Back to the equation:

-(-8y+8)



We get rid of parentheses

8y+8y-8-8=0

We add all the numbers together, and all the variables

16y-16=0

We move all terms containing y to the left, all other terms to the right

16y=16

y=16/16

y=1

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