4(2y-1)=2(3y+4)

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Solution for 4(2y-1)=2(3y+4) equation: 



4(2y-1)=2(3y+4)

We move all terms to the left:

4(2y-1)-(2(3y+4))=0

We multiply parentheses

8y-(2(3y+4))-4=0



We calculate terms in parentheses: -(2(3y+4)), so:

2(3y+4)

We multiply parentheses

6y+8

Back to the equation:

-(6y+8)



We get rid of parentheses

8y-6y-8-4=0

We add all the numbers together, and all the variables

2y-12=0

We move all terms containing y to the left, all other terms to the right

2y=12

y=12/2

y=6

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