4(2y-1)+11=(3y-2)-17

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Solution for 4(2y-1)+11=(3y-2)-17 equation:



4(2y-1)+11=(3y-2)-17
We move all terms to the left:
4(2y-1)+11-((3y-2)-17)=0
We multiply parentheses
8y-((3y-2)-17)-4+11=0
We calculate terms in parentheses: -((3y-2)-17), so:
(3y-2)-17
We get rid of parentheses
3y-2-17
We add all the numbers together, and all the variables
3y-19
Back to the equation:
-(3y-19)
We add all the numbers together, and all the variables
8y-(3y-19)+7=0
We get rid of parentheses
8y-3y+19+7=0
We add all the numbers together, and all the variables
5y+26=0
We move all terms containing y to the left, all other terms to the right
5y=-26
y=-26/5
y=-5+1/5

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