4(2y+5)+3(y+1)=34

Solution for 4(2y+5)+3(y+1)=34 equation:

Simplifying
4(2y + 5) + 3(y + 1) = 34

Reorder the terms:
4(5 + 2y) + 3(y + 1) = 34
(5 * 4 + 2y * 4) + 3(y + 1) = 34
(20 + 8y) + 3(y + 1) = 34

Reorder the terms:
20 + 8y + 3(1 + y) = 34
20 + 8y + (1 * 3 + y * 3) = 34
20 + 8y + (3 + 3y) = 34

Reorder the terms:
20 + 3 + 8y + 3y = 34

Combine like terms: 20 + 3 = 23
23 + 8y + 3y = 34

Combine like terms: 8y + 3y = 11y
23 + 11y = 34

Solving
23 + 11y = 34

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-23' to each side of the equation.
23 + -23 + 11y = 34 + -23

Combine like terms: 23 + -23 = 0
0 + 11y = 34 + -23
11y = 34 + -23

Combine like terms: 34 + -23 = 11
11y = 11

Divide each side by '11'.
y = 1

Simplifying
y = 1